javascript - invoking method using ajax at code behind in asp.net -


hey making simple web form product detail insertion web page. trying insert using ajax call. without ajax works .. $.ajax not invoking code behind static method, no idea wat's issue. here's code: 

$(document).ready(function () {     $("#submit").click(function () {         var cat = document.getelementbyid('dropdownlist1').value;         var nm = document.getelementbyid('name').value;         var cde = document.getelementbyid('code').value;         var dt = document.getelementbyid('dt').value;          var price = document.getelementbyid('price').value;         var f3 = document.getelementbyid('ty').innerhtml;          alert("you clicked " + cat + " - " + nm + "-" + cde + "-" + dt +                  "-" + price + "-" + f3 +  "-");         //////////////uptil here alert gives right value.         $.ajax({            method: "post",            contenttype: "application/json",             url: "home.aspx/ins",            datatype: "json",            data: "{'name :' + nm + 'code :' + cde +'category :'+ cat +                'date :'+ dt +'price :'+ pr +'img_name :' + f3}",            //data:"{}",            //async: false,            success: function (response) {                alert("user has been added successfully.");                window.location.reload();            }        });     }) }); 
//////////////////////////////// here code behind method:  [system.web.services.webmethod] public static void ins(string name,string code,string category, datetime date,    int price,string img_name) {     productclass pc = new productclass();     pc.pr_name = name;     pc.code = code;     pc.category = category;     pc.expiry = date;     pc.price = price;     pc.pr_image = img_name;      dalinsert di = new dalinsert();     bool flag = di.insert(pc); }

correct way pass data ajax post via webmethod this.

var params = "{'name' :'" + nm + "', 'code' :'" + cde + "', 'category' :'" + cat + "', 'date' : '" + dt + ", 'price' :'" + pr + "' , 'img_name' :'" + f3 + "' }" // declare above $.ajax...

data: params, //use above in $.ajax... .


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