c++ - Automatic number issued by the system with array -

i wrote:

 string a[100] = { "b", "f", "r", "p", "d", "\0" }; class bd{ //data member static int id; //....... };    void setid(int d){ id = d;     (int = 0; < 5; i++){         id = + 1;         user[id];     } cout << " id : " << id << endl;     }     int bd::id = 0; 

in code, has array include name of user , each user different id number in run (output) 5 ! know it's logical error. when enter : b

id : 5 

but want print :

 if user enter name  `b`   id : 1  

if user enter name f

id : 2 

you rewriting id in loop

    id = + 1; 

thus last used in body of loop equal 4 id = 5

edit: if want find string in array of strings , return index + 1 function can like

int getid( const std::string &s ) {      string a[100] = { "b", "f", "r", "p", "d", "\0" };      int id = 0;      while ( a[id] != "\0" && a[id] != s ) ++id;      return a[id] == "\0" ? 0 : id + 1; } 

however seems not understand difference between objects of type std::string , character arrays , string literals. need different function showed.