sql - Query to get number of % sign = length of string in the next row in Oracle 10g -


is there sql query in oracle10g can give desired output given required in below sample. query should print name first , in second row should print "%" equal in number length of string.

could please help?

below sample of table column

jim john michael

and output should come below : 

jim %%% john %%%% michael %%%%%%%

this considered issue presentation logic, not database logic. however, 1 option use union all, , length , rpad correct number of % signs. you'd need establish row number keep order together.

here's 1 approach:

select name (   select name, rownum rn   yourtable   union   select rpad('%', length(name), '%') name, rownum + 1 rn   yourtable ) t order rn, name

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