python - How do you split a list into evenly sized chunks? -

i have list of arbitrary length, , need split equal size chunks , operate on it. there obvious ways this, keeping counter , 2 lists, , when second list fills up, add first list , empty second list next round of data, potentially extremely expensive.

i wondering if had solution lists of length, e.g. using generators.

i looking useful in itertools couldn't find useful. might've missed it, though.

related question: what “pythonic” way iterate on list in chunks?

here's generator yields chunks want:

def chunks(l, n):     """yield successive n-sized chunks l."""     in range(0, len(l), n):         yield l[i:i + n] 

---

import pprint pprint.pprint(list(chunks(range(10, 75), 10))) [[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],  [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],  [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],  [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],  [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],  [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],  [70, 71, 72, 73, 74]] 

---

if you're using python 2, should use xrange() instead of range():

def chunks(l, n):     """yield successive n-sized chunks l."""     in xrange(0, len(l), n):         yield l[i:i + n] 

---

also can use list comprehension instead of writing function. python 3:

[l[i:i + n] in range(0, len(l), n)] 

python 2 version:

[l[i:i + n] in xrange(0, len(l), n)]