algorithm - Determining the big-O runtimes of loop with inner loop repeat time is const -


i have function

for(int i=0;i<n; i++) {   b[i]=0;   for(int j=0;j<5;j++)   {      b[i]=a[j+i]   } }

i need calculate big-o of above function. answers is:
inner loop run 5n time => o(n). total complexity o(n). think have mistake in calculations, don't know mistake.

no, haven't made mistake. correct in thinking , solution perfect!

the outer-loop run n-times , inner loop runs 5(constant) times.

therefore, loops complexity o(5*n) = o(n) , other statements of constant time-complexity.

since, 5*n times execution of program means o(n) time-complexity of program.


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