Scheme (Racket) Getting a random boolean with probably 0 < p < 1 -


in racket scheme, best way random boolean true probability 0 <= p <= 1?

here solution, make probabilities explicit:

#lang racket (require math) (define d (discrete-dist '(#t #f) '(0.6 0.4))) (sample d 10)

sample output:

'(#f #t #t #t #t #f #t #f #f #t)

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