g++ - Overloading function in C++ as unsigned char and unsigned int result in ambiguous -

i have overloaded functions:

void wypisz(unsigned int32 x, int n = 1); void wypisz(unsigned char x, int n = 1); 

here code rise them:

main() {     wypisz((int32)(32), 7);     wypisz('a', 7);     return 0; } 

and when try compile using g++ error:

test.cpp: in function 'int main()':

test.cpp:10:21: error: call of overloaded 'wypisz(int, int)' ambiguous wypisz((int)(32), 7);

test.cpp:10:21: note: candidates are:

test.cpp:5:6: note: void wypisz(unsigned int, int) void wypisz(unsigned int x, int n = 1);

test.cpp:6:6: note: void wypisz(unsigned char, int) void wypisz(unsigned char x, int n = 1);

when remove unsigned compile fine.

is there way call method - wha ti should change in call statement? unfortunatelly can not change in declaration = must stay are.

the problem that, in function call, casting int32, neither unsigned char nor unsigned int32. in fact, implicitly castable either of them (the compiler can convert automatically). however, because can convert either automatically, doesn't know which convert to, , why call ambiguous.

to call method unambiguously, cast unsigned int32:

wypisz((unsigned int32)32, 7); 

now, compiler doesn't have implicit casting, since there exact match. instead, calls right function.