python - Find the Number of even intergers in a sequence -

enter arbitrary sequence of integers @ keyboard, , prints number of positive integers user enters.

def find_even_count():           count = 0           x = raw_input("enter value, or q quit: ")           while (x != "q") , (x > 0):               num in x:                   if (int(x) % 2 == 0):                       count += 1                       entry = raw_input("enter value, or q quit: ")           return count 

i have gotten far not working ideas?

if counting them entered there no need iterate.

def find_even_count():     count = 0     x = raw_input("enter value, or q quit: ")     while (x != "q") , (x > 0):         if (int(x) % 2 == 0):             count += 1         x = raw_input("enter value, or q quit: ")     return count 

on other hand if had sequence of numbers getting number of evens o(n) , can written 1 pythonic line.

numberofevens = sum([1 if k%2==0 else 0 k in sequence])