language agnostic - What is the cleanest way to round a value to nearest 45 degrees? -


i have same question question here.

the user asked:

i wrote return nearest 45 degree angle. 0, 45, 90, 135...

it feels there must better way of doing though. working fine looks messy.

    public function nearestdeg(degs:int):int {          if (degs >= 0 && degs <= 45) {             if (degs <= 23) {                 return 0;             }else {                 return 45;             }         }          if (degs > 45 && degs <= 90) {             if (degs <= 68) {                 return 45;             }else {                 return 90;             }         }          if (degs > 90 && degs <= 135) {             if (degs <= 113) {                 return 90;             }else {                 return 135;             }         }          if (degs > 135 && degs <= 180) {             if (degs <= 158) {                 return 135;             }else {                 return 180;             }         }          if (degs > 180 && degs <= 225) {             if (degs <= 203) {                 return 180;             }else {                 return 225;             }         }          if (degs > 225 && degs <= 270) {             if (degs <= 248) {                 return 225;             }else {                 return 270;             }         }          if (degs > 270 && degs <= 315) {             if (degs <= 293) {                 return 270;             }else {                 return 315;             }         }          if (degs > 315 && degs <= 360) {             if (degs <= 338) {                 return 315;             }else {                 return 360;             }         }           return 0;      }

what cleanest way round value nearest 45 degrees?

i'd divide value 45°, round, , multiply 45°. pseudocode:

deg = round(deg / 45) * 45;

assumption: / operator returns floating-point representation , not perform integer division. if specific language not treat should handled explicitly (e.g., divide 45.0 instead of 45).


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