angularjs - $parse vs $eval ? which one is best practice? -


i know $parse , $eval both operate on angular expressions.then why angular team created these 2 ?

i checked in angular library, $eval defined that:

$eval: function(expr, locals) {         return $parse(expr)(this, locals);       }

so difference between :

$parse(expr)(context, locals);

and 

$eval: function(expr, locals) {         return $parse(expr)(this, locals);       }

i want know 1 best practice ? , when use these 2 ?

as noticed, 

$parse(expr)($scope, locals)

is exactly equivalent to

$scope.$eval(expr, locals)

but, $parse more "fundamental" operation $eval, , so, $parse once in 1 place (for example, in compile function of directive):

var parsedexpr = $parse(tattrs.p1);

and use repeatedly elsewhere (for example, in controller function)

var childscope1 = $scope.$new(); var childscope2 = $scope.$new();  var r1 = parsedexpr(childscope1); var r2 = parsedexpr(childscope2);

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