permutation - Is there an efficient way of generating numbers with repeated digits in Python? -


i trying generate 5 digit numbers out of {1,2,3,4,5,6,7,8,9} such digit can repeated @ twice. is, numbers 12345, 11267, 11226 allowed 11134 or 11115 not allowed.

i can write code multiple loops perhaps, wondering if there shorter, more elegant methods available. example, itertools.product('123456789', repeat=5) generate such 5 tuples (9^5 in total) or itertools.permutations(''123456789',5) generate 5 tuples no repetitions (9x8x7x6x5 in total). wondering there way use these tools generate numbers of form 11235 , 11224 nothing else without going through multiple loops , like.

unless i've misunderstood question, using 

itertools.permutations('112233445566778899',5)

should trick.

edit: included repeats, since had 2 of each digit. wrapping in set seems solve that:

set(itertools.permutations('112233445566778899',5))

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