bash - Regex to extract/output quoted strings from a file -

i wrote simple regular expression output quoted strings file

cat mobydick.txt |  while read line; echo -n "$line "; done | grep -op '[^"]*"\k[^"]*'

this have far

for example, when run one-liner on file mobydick.txt output in single line instead of new line separated strings.

could me script?

expected output --> when above script run on mobydick.txt
"from twenty-fifth year date life."
"call me ishmael."

above input file can downloaded url

using gnu grep(1) (other incarnations of grep(1) don't have -p):

tr '\n' ' ' <mobydick.txt | grep -p -o '(?<=\s)"[^"]+"(?=\s)'

more accurate, using pcregrep(1):

pcregrep -m -o '(?<=^|\s)"[^"]+"(?=$|\s)' mobydick.txt

UV code