haskell - How to delete unbuildable goal? -


i remove files no longer have source without cleaning.

is there support partially cleaning incremental build? in case, guess compare against set of source files consumed in previous builds , define how clean gone.

main = shakeargs shakeoptions { shakeverbosity = diagnostic } $     want [".build"]     phony ".build" $       files <- getdirectoryfiles "." ["//*.txt"]       let goals = map (-<.> "") files       need goals     "*" %> \out ->       stdout o <- cmd $ "sort " ++ (out ++ ".txt")       writefile' out o 

using shakeargsprune can define function gets passed live files afterwards. can write like:

import development.shake import development.shake.filepath import development.shake.util import system.directory.extra import data.list import system.io  pruner :: [filepath] -> io () pruner live =     present <- listfilesrecursive "output"     mapm_ removefile $ map tostandard present \\ map tostandard live  main :: io () main = shakeargsprune shakeoptions pruner $     ... rules go here ... 

this deletes files in output not generated , up-to-date according build system stands. complete example see http://neilmitchell.blogspot.co.uk/2015/04/cleaning-stale-files-with-shake.html.

the shakeargsprune function available in shake-0.15.1 , above, based on shakelivefiles feature has been available longer , can used directly if desire.


Comments

Popular posts from this blog

shopping cart - Page redirect not working PHP -

php - How to modify a menu to show sub-menus -

python - Installing PyDev in eclipse is failed -