How to avoid separators to be printed on screen when printing a whole array in bash script -

i have strange issue script , know if exists solution rid of it.

i have put in script test out :

#!/bin/bash  # clear screen clear  # define array array=("\e[2;3hline one" "\e[3;3hline two" "\e[4;3hline three")  # change background color "teal" , foreground color "black" echo -e "\e[0;30m\e[46m"  # print each line 1 one on screen # works expected, nothing echo -e "${array[0]}" echo -e "${array[1]}" echo -e "${array[2]}"  # exact same text, moved text below previous 1 make easier compare array=("\e[6;3hline one" "\e[7;3hline two" "\e[8;3hline three") # print entire array in 1 shot, gain speed # not work expected there "space" @ end of 2 first lines echo -e "${array[@]}"  # reset colors normal echo -e "\e[0m" 

when launching it, can see in 2nd printing there "space" @ end of 1st , 2nd line.

the question : how rid of these spaces ?!

note : need formating , need print whole array @ once... , way, played ifs , character substitution nothing worked expected far...

edit : solution proposed cyrus below using "printf" instead of "echo" seems work expected (i'm not sure of pros , cons of using instead of "echo" builtin job).

solution :

printf "%b\n" "${array[@]}" 

instead of :

echo -e "${array[@]}" 

thanks again cyrus help.

replace

echo -e "${array[@]}" 

by

printf "%b\n" "${array[@]}"