How to print a nested list of objects with the highest sum in python -


i'm still learning python , i'm still having tough time working objects, i'm trying write program calculates critical path of set of activities in project, i've been able critical path of activities , they're stored list of nested objects each object having it's different properties id, predecessor , duration, problem i'm having print out result properly, want print out path has longest duration , path gives value

class criticalpath:      def __init__(self):         '''         initialize variables we're going use calculate critical path         '''         self.id = none         self.pred = tuple()         self.dur = none         self.est = none         self.lst = none         #list store objects         self.all_objects = list()      def set_properties(self, name, predecessor, duration):         self.id = name         self.pred = tuple(predecessor)         self.dur = duration   def main():     #starting_nodes = list()     object_list = list()      = criticalpath()     a.set_properties('a', '0', 3)      b = criticalpath()     b.set_properties('b', '0', 6)      c = criticalpath()     c.set_properties('c', 'a', 1)      d = criticalpath()     d.set_properties('d', 'b', 4)        tmp_list = list()     tmp_list.append(a)     tmp_list.append(c)     object_list.append(tmp_list)      tmp_list = list()     tmp_list.append(b)     tmp_list.append(d)     object_list.append(tmp_list)       print('the total duration of project {}'.format(max([sum([node.dur node in object]) object in object_list])))     #print(max(object_list.id, key=sum(object_list.dur)))   if __name__ == '__main__': main()

i've been able print out total duration in case 10, last line commented out last attempt @ comparing objects id in object_lists based on individual duration property 'id' , 'dur' of each object, want output this

the critical path of project b==>d , total duration of project 10

class criticalpath:      def __init__(self):         '''         initialize variables we're going use calculate critical path         '''         self.id = none         self.pred = tuple()         self.dur = none         self.est = none         self.lst = none         #list store objects         self.all_objects = list()      def set_properties(self, name, predecessor, duration):         self.id = name         self.pred = tuple(predecessor)         self.dur = duration   def main():     #starting_nodes = list()     object_list = list()      = criticalpath()     a.set_properties('a', '0', 3)      b = criticalpath()     b.set_properties('b', '0', 6)      c = criticalpath()     c.set_properties('c', 'a', 1)      d = criticalpath()     d.set_properties('d', 'b', 4)      tmp_list = list()     tmp_list.append(a)     tmp_list.append(c)     object_list.append(tmp_list)      tmp_list = list()     tmp_list.append(b)     tmp_list.append(d)     object_list.append(tmp_list)      print(object_list)      print('the total duration of project {}'.format(max([sum([node.dur node in object]) object in object_list])))     print([path.id path in max(object_list, key=lambda ls: sum(obj.dur obj in ls))])   if __name__ == '__main__': main()

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